The quota for Scheduled Castes, Scheduled Tribes, Other Backward Classes and Economically Weaker Section in government organisations can be replaced with a quota equal to the effective illiteracy rate of the state or country for people chosen on the basis of normalised scores for parents’ education and combined annual income for both parents rounded off upto 4 decimal places. Candidates who have annual parental income less than ₹8,00,000 and have scored >= 80% of the cutoff score determined for the general category may be arranged in ascending order of normalised scores. Suppose there are 100 seats available for reserved category and 200 people apply for it, the first 100 candidates can be chosen. In case of a tie the candidate with lower total years of parents’ education could be given higher priority.
Effective Illiteracy rate = 100 - Effective Literacy Rate
Normalised Score = {(sum of parental income) / ₹8,00,000 +
(sum of parents' years of education) / (10 + 10)}
The percentage of seats reserved may be revised every 10 years after the publication of the census report.
Effective literacy rates for India and Madhya Pradesh are taken from page 6 and 14 respectively of this pdf:
Rules for rounding off can be adopted from this webpage:
http://www.chemteam.info/SigFigs/Rounding.html
Example 1:
For a job in Madhya Pradesh State Textile Co.Ltd, if the cutoff for general category candidates is determined to be 200 marks out of 300, 30% of seats can be reserved for candidates who score >=160 marks. A candidate who secures 185 marks whose mother earns ₹2,50,000 per annum as a tailor having studied upto 4th standard and father earns ₹4,00,000 per annum as a mason having studied upto 7th standard may be given higher preference than a candidate who secures 187 marks whose mother earns ₹0 working as a housewife having studied upto 5th standard and father earns ₹2,90,000 per annum as an accountant having studied B.Com for 3 years.
Calculations are as follows:
Normalised Score of 1st candidate =
{( ₹2,50,000 + ₹4,00,000 ) / ₹8,00,000 + (4 + 7) / (10 + 10)}
= 1.3625
Normalised Score of 2nd candidate =
{( ₹0 + ₹2,90,000 ) / ₹8,00,000 + (5 + 15) / (10 + 10)}
= 1.3625
Since both of them have equal scores the 1st candidate will be preferred because his parents have lower total years of education.
Example 2:
For a job in the Food Corporation of India, if the cutoff for general category candidates is determined to be 350 marks out of 500, 26% of seats can be reserved for candidates who score >=280 marks. The normalised score for a candidate securing 332 marks whose mother is a soldier’s widow who did not remarry earning ₹3,30,000 per annum as family pension having studied upto 8th standard is calculated as:
Normalised Score of candidate =
{( ₹3,30,000 + 0 ) / ₹8,00,000 + (8 + 0) / (10 + 10)}
= 0.8125
Assuming a linear relationship between effective literacy rate (X) and years (Y), I entered the data from page 6 of the below pdf:
In the webpage: http://www.alcula.com/calculators/statistics/linear-regression/
as follows:
I got the following output:
The relationship between effective literacy rate (X) and years (Y) turns out to be:
Y=1932.359847107 + 1.0783931531719X
By substituting X = 100, we get Y = 2040. So we can expect that India will effectively become 100% literate by 2040. If any state achieves 100% literacy before that year it can discontinue reservation on the basis of parental income and parental education.
Credit: http://www.thehindu.com/opinion/lead/a-new-edifice-for-reservations-scheme/article7604312.ece
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